when testing two identical connectors connected one against the other, I get from my network analyzer the S-parameters file concerning the cascade. How can I process in Genesys this S-parameter file in order to get the half circuit S-parameters, hence having one connector's characterization? This would be very useful since I don't have any other way to test directly the connectors (i.e. specific adaptors having a sufficient precision level). I understand that this works in the assumption of two identical connectors, which is actually the case; I know that from a mathematical point of view the S-parameter matrix should be transformed in a T-matrix, squared, and then back again to the S-parameter matrix.

My input s-parameter is commonly in the form of a Touchstone file.

Any solutinon will be very welcome!

My input s-parameter is commonly in the form of a Touchstone file.

Any solutinon will be very welcome!

It needs:

1. Calculate any transmission matrix data (T or ABCD) from S-matrix data. GENESYS does not have functions for this conversion (S to T, or S to ABCD), and this code has to be developed, using Genesys equations.

2. Calculate 1 connector transmission matrix = square root of the matrix, it may be found using GENESYS "Math" language, if the solution exist. According matrix theory it exist for Hermitian positive defined matrix only (http://en.wikipedia.org/wiki/Matrix_square_root), which demands additional preprocessing measured data to exclude instrument errors. Looking T vs. S equations for 2-port (http://en.wikipedia.org/wiki/S-paramete ... Parameters) the T matrix is Hermitian (T12 = conj(T21) )the only if it's lossless and S11=S22

T12 = S11/S21

T21 = -S22/S21

which does not work for lossy or non-symmetrical connectors.

3. Convert the calculated transmition matrix to S. Again, Genesys does not have functions for this conversion (T to S or ABCD to S), which code also has to be developed.

As follows from that this is not trivial task, needed a lot of efforts, but GENESYS equation languages allow to solve it (when it has solution).