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How to apply 1MHz waveform to UUT by 3070

Question asked by leo on Jun 27, 2010
Latest reply on Aug 16, 2012 by yenuplaotis

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source sine/square.. can provide 1-20KHz signal

source arb seems to be able to provide large frequency waveform but I can not find the frequency limit description.The statement is like:
source arb, samples 1024, repetition 32768, voltages "WaveForm", on.
Sample can be 1024 and repetition can be 32768. If my voltages data block is as following:
0,5,0,5.......(repeat 512 of "0,5"). Can I get the square wave form at 512x32768 Hz frequency? The notes says"Note that the output is controlled by a two-pole filter with a 3db bandwidth at 120KHz". Does it mean the upper limit of arb output is 120kHz.

Then maybe the only way to provide 1Mhz is by the digital dirver?

No one else has this question

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OldHand Jun 28, 2010 3:37 AM

Hi Leo,

"
Does it mean the upper limit of arb output is 120kHz.
"

No, it means what you get out will not be a square wave and any 120kHz components will be 3dB (half the level) of the 20kHz components.

"
Then maybe the only way to provide 1Mhz is by the digital dirver?
"

I think this would be your best bet. What do you need to do?

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leo Jun 28, 2010 6:31 AM

Thanks, Oldhand.UUT need 1Mhz square waveform to stim and measure the voltage output.
PS. Are you from agilent? I think you are very senior. where are you located?

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OldHand Jun 28, 2010 7:08 AM

Hi Leo,

Not from Agilent, but I have been programming 3070 testers in the UK since 1995.

What you need sounds like a mixed test.

I can't remember the exact syntax but in essance :-

assign INPUT to nodes "your board node name"
....
inputs INPUT
....
vector cycle 500n
receive delay 100n ! does not matter - nothing being measured
...
...
vector High
set INPUT to "1"
end vector
vector Low
set INPUT to "0"
end vector

unit "test"
execute High ! must execute one digital vector before doing analog stuff
continue analog ! set up the analog detector

repeat 10000 times ! 10 ms of input signal
    execute High
    execute Low
end repeat
repeat 10000 times ! 10 ms of input signal
    execute High
    execute Low
end repeat
execute High trigger dcv !the ASRU goes of and measures a voltage
execute Low
repeat 10000 times ! 10 ms of input signal while measure is completing
    execute High
    execute Low
end repeat

continue analog
end unit

.....
analog test

test powered mixed
connect i to nodes "your output high node"
connect l to nodes "your output low node"

detector dcv, expect 10
continue digital
fetch Result
report analog 10, 8, Result
end test

The digital test provides your square wave (500ns low + 500ns high = 1us period = 1MHz)
The analog detector gets set up, but triggered while the digital section is running.
Then the result is fetched and compared within limits

As I Said, check the syntax - the manual is good, if you know where to look

Good luck

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yenuplaotis @ OldHand on Aug 16, 2012 11:32 AM

A simple way to generate a square wave with a frequency in the range 625KHz - 20MHz is the "inputs formatted clock" command in vcl file.
You can find it in the Agilent online help syntax reference section.
Attached is a simple mixed test where I wanted to apply a 10Mhz square wave to the input of a delay line and measure 10Mhz on each of the devices 5 outputs.

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digital1.3 KB
analog1.3 KB

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4 Replies

OldHand Jun 28, 2010 3:37 AM
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Correct Answer
Hi Leo,

"
Does it mean the upper limit of arb output is 120kHz.
"

No, it means what you get out will not be a square wave and any 120kHz components will be 3dB (half the level) of the 20kHz components.

"
Then maybe the only way to provide 1Mhz is by the digital dirver?
"

I think this would be your best bet. What do you need to do?
Like • Show 0 Likes0
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leo Jun 28, 2010 6:31 AM
Mark Correct
Correct Answer
Thanks, Oldhand.UUT need 1Mhz square waveform to stim and measure the voltage output.
PS. Are you from agilent? I think you are very senior. where are you located?
Like • Show 0 Likes0
Actions
OldHand Jun 28, 2010 7:08 AM
Mark Correct
Correct Answer
Hi Leo,

Not from Agilent, but I have been programming 3070 testers in the UK since 1995.

What you need sounds like a mixed test.

I can't remember the exact syntax but in essance :-

assign INPUT to nodes "your board node name"
....
inputs INPUT
....
vector cycle 500n
receive delay 100n ! does not matter - nothing being measured
...
...
vector High
set INPUT to "1"
end vector
vector Low
set INPUT to "0"
end vector

unit "test"
execute High ! must execute one digital vector before doing analog stuff
continue analog ! set up the analog detector

repeat 10000 times ! 10 ms of input signal
    execute High
    execute Low
end repeat
repeat 10000 times ! 10 ms of input signal
    execute High
    execute Low
end repeat
execute High trigger dcv !the ASRU goes of and measures a voltage
execute Low
repeat 10000 times ! 10 ms of input signal while measure is completing
    execute High
    execute Low
end repeat

continue analog
end unit

.....
analog test

test powered mixed
connect i to nodes "your output high node"
connect l to nodes "your output low node"

detector dcv, expect 10
continue digital
fetch Result
report analog 10, 8, Result
end test

The digital test provides your square wave (500ns low + 500ns high = 1us period = 1MHz)
The analog detector gets set up, but triggered while the digital section is running.
Then the result is fetched and compared within limits

As I Said, check the syntax - the manual is good, if you know where to look

Good luck
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- yenuplaotis @ OldHand on Aug 16, 2012 11:32 AM
  Mark Correct
  Correct Answer
  A simple way to generate a square wave with a frequency in the range 625KHz - 20MHz is the "inputs formatted clock" command in vcl file.
  You can find it in the Agilent online help syntax reference section.
  Attached is a simple mixed test where I wanted to apply a 10Mhz square wave to the input of a delay line and measure 10Mhz on each of the devices 5 outputs.
  Attachments
  - digital1.3 KB
  - analog1.3 KB
  Like • Show 0 Likes0
  Actions

How to apply 1MHz waveform to UUT by 3070

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