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correction amplitude

Question asked by ocean on Nov 14, 2006
Latest reply on Nov 16, 2006 by mfredrik

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hi
I generate a signal 5 GHz with -10 db, when he through filter butterworth de amplitude of my signal is 0 db.
My question: what I must add after my filter to have amplitude -10db of my signal.

thankx

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mfredrik Nov 14, 2006 8:39 AM
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Don't know how you model your filter, but if you use an ADS system mdel, such as BPF_Butterworth, LPF_Butterworth..., then you can just set the loss in the passband for the filter to 10 dB.

Double-click on the filter
Set the IL parameter to 10

Now the passband loss should be 10 dB when you simulate it again.

-Mats
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mfredrik Nov 16, 2006 1:43 AM
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The IL parameter does work for me. Don't know what could be wrong in your case. Anyway, if the IL parameter doesn't work for you, then you could add a loss after the filter using the You can do that in many ways. Amplifier2, S2p_Eqn, Attenuator component etc etc. You can find the Attenuator component on the System-Passive palette. But if you this then you isolate the rest of your circuit from any mismatch previous in the system. If you care about mismatch loss/passband ripple etc then this might not be the best way to go.
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correction amplitude

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