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What's the unit of Acquisition Memory

Question asked by George5 on May 27, 2009
Latest reply on Jun 1, 2009 by algoss

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In service guide for 8000 Series Infiniium Oscilloscopes(PN: D8064-97006), I found below section,

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Factory-Installed
Instrument Options
040 Increase acquisition memory to 8 M on half channel and 4 M on all channels
080 Increase acquisition memory to 16 M on half channel and 8 M on all channels
...
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I just wonder what the unit of acquisition memory is, M pts?

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algoss May 28, 2009 5:19 AM
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Yes, the unit is Mpts, or more correctly digital samples, before interpolation. So, "8 M on half channel and 4 M on all channels" means 8M depth if one or two (ch1 &ch 3 or ch2 & ch4) channels are turned on. As soon as another channel is turned on, or a channel from the other set (i.e. ch1 & ch2) is turned on, the depth drops by one half.
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George5 May 30, 2009 7:16 PM
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Thanks a lot for your reply!
I have another question about this, on Agilent 8104A, I found, sometimes, memory depth is 1,048,576(1024 x 1024?) pts.
So, why not 1,000,000 pts? Does it relate to vertical resolution(8-bit or others)?
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algoss Jun 1, 2009 4:52 AM
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You can set the depth to anything that you want, between 16 points (which I believe is the minimum) and the maximum, which is a "digital" 1Mpoints. By convention, 1K is 1024 and 1M is 1048576.
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What's the unit of Acquisition Memory

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