Dear supporter,

In my experiment, I measured the area of signals.

I observed the unit of the measure result is pVs.

Does this means volt* picosecond？Actually, I want to

get charge of signals, so I divided the result by 50ohm

(since the oscilloscope is DC coupling and 50ohm input impedance).

In the view of unit, I got it, volt*picosecond/ohm=amp*picosecond,

is just the unit of charge. But I still wondered my calculation is correct or

not? If it's not correct, how can I get the output signal's charge via our

Agilent 90804A?

Thanks a lot!

Best regards,

J.H.L.

In my experiment, I measured the area of signals.

I observed the unit of the measure result is pVs.

Does this means volt* picosecond？Actually, I want to

get charge of signals, so I divided the result by 50ohm

(since the oscilloscope is DC coupling and 50ohm input impedance).

In the view of unit, I got it, volt*picosecond/ohm=amp*picosecond,

is just the unit of charge. But I still wondered my calculation is correct or

not? If it's not correct, how can I get the output signal's charge via our

Agilent 90804A?

Thanks a lot!

Best regards,

J.H.L.

Thanks for your reply!

I am sorry but have to say, do you know how to get an "official" confirmed answer

on this case?

On the other hand, if the area measurement does not represent charge measurement.

why Agilent design such a measuring item, I mean area.

Thanks again!