Dear All,

Taking an example of Differential signal to single ended signal, how does the PNA the gets the measurement data. In other words, If i use modulation power of 2dBm, what as input differential signal, what is the voltage it transmitted to my load (assume 50 ohm). What is the resultant voltage output out from the single ended channel? What would be the resultant phase data at my single ended channel assuming load is ideal transmission line.

Looking forward if anyone can help to clarify. Thank you in advance.

Taking an example of Differential signal to single ended signal, how does the PNA the gets the measurement data. In other words, If i use modulation power of 2dBm, what as input differential signal, what is the voltage it transmitted to my load (assume 50 ohm). What is the resultant voltage output out from the single ended channel? What would be the resultant phase data at my single ended channel assuming load is ideal transmission line.

Looking forward if anyone can help to clarify. Thank you in advance.

In normal, the 9 single-ended S-pararemters are acquired, through 3 measurements: power at port1, power at port 2, power at port 3, and the differential and common mode equivalent parameters are computed.

In True Mode, the three sets of measurements become: single-ended power at single ended port, differential power (turning 2 sources on and setting their phase to 180 degrees) at balanced port, common mode power (turning on 2 sources, and setting their phase to 0 degrees). The differential-to-single, differential-to-differential reflection, and common-to-differential are now computed and dispayed as desired.

I'm not sure what you mean by modulated power. If you mean source power, then it depends upon the mode above.

If you are in true mode, and you set the true mode power to 2 dBm, then each single ended source will be set to 3 dB below that power. The balanced power will be the sum of the two and thuse 2 dBm, and will have 2dBm provided your DUT is 100 ohms differential. The differential voltage will be .4 volts RMS or .56 volts peak, if I did my math right (1.12 v p-p).

The if the DUT is a lossless impedance matched combiner, then the power into the single ended port will be 2 dBm, which will be .28 v RMS, or .4 volts peak. Again, presuming I did my math right.

The power into a single ended DUT will be 2 dBm, provided that their is no loss through the