Hello,

I'm using the MXA N9020A to perform Frequency Measurements from a generator.

The difference between set frequency and measured frequency divided by the set frequency was roughly 0.1 ppm

Can I declare that to be the accuracy of my test?

Ari

I'm using the MXA N9020A to perform Frequency Measurements from a generator.

The difference between set frequency and measured frequency divided by the set frequency was roughly 0.1 ppm

Can I declare that to be the accuracy of my test?

Ari

The frequency accuracy of the MXA can be calculated by using the Frequency accuracy specification for the N9020A MXA in the Specifications Guide below:

http://cp.literature.agilent.com/litweb/pdf/N9020-90113.pdf?cmpid=zzfindmxa_specifications

On page 22 there is an equation given for the frequency readout accuracy:

±(marker freq × freq ref accy. + 0.25% × span + 5% × RBWa + 2 Hz + 0.5 × horizontal resolution)

The Frequency Reference Accuracy equation is given below for the MXA on page 21 :

±[(time since last adjustment × aging rate) + temperature stability + calibration accuracy]

The values for the above term are given on this page as well.

This assumes that the references between the source and the analyzer are not locked.

Regards -