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Output Data

Question asked by mojedy on Oct 17, 2013
Latest reply on Oct 22, 2013 by algoss

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Hi,

I measured some data (delay between two output signal) with agilent MSO7104A Oscilloscope .

I save the result on USB( to csv file), and now I want to analyse them. when I open the saved file, I saw the second, are negative!! how it can happen .. can anyone help me how I can show the data : Here is some of the data :

          x.axis              X1              X3
1         second            Volt            Volt
2    -500.00E-06   -18.75000E-03        +0.0E+00
3    -499.00E-06   +12.50000E-03   -31.25000E-03
4    -498.00E-06   +12.50000E-03   -31.25000E-03
5    -497.00E-06   -18.75000E-03   +31.25000E-03
6    -496.00E-06   +43.75000E-03        +0.0E+00
7    -495.00E-06   -18.75000E-03        +0.0E+00
8    -494.00E-06   +12.50000E-03        +0.0E+00
9    -493.00E-06   +12.50000E-03        +0.0E+00
10   -492.00E-06   +12.50000E-03        -0.0E+00
11   -491.00E-06   +12.50000E-03   -31.25000E-03
12   -490.00E-06   +12.50000E-03   +31.25000E-03
13   -489.00E-06   +12.50000E-03   -31.25000E-03
14   -488.00E-06   -18.75000E-03   +31.25000E-03
15   -487.00E-06   -18.75000E-03        -0.0E+00
16   -486.00E-06   +12.50000E-03   -31.25000E-03
17   -485.00E-06   -18.75000E-03   +31.25000E-03
18   -484.00E-06   +12.50000E-03   -31.25000E-03
19   -483.00E-06   +12.50000E-03   +31.25000E-03
20   -482.00E-06   +12.50000E-03   -31.25000E-03
21   -481.00E-06   +43.75000E-03        +0.0E+00

BR,
Mozhdeh

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algoss

Oct 18, 2013 4:58 AM

What are you expecting to see? What does your signal look like?

Al

Disclaimer: For more reliable response, you should consider calling your local Agilent Technical Call Center. The Agilent Forums are monitored on an "as available" basis, and aren't necessarily the fastest way to get technical questions answered.

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ksmith

Oct 21, 2013 8:42 AM

Modern digital scopes can capture pre-trigegr data. The trigger time is defined as T = 0, so any timne befoire that is negative, i.e. before the trigger event.

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algoss

@ ksmith on Oct 22, 2013 5:37 AM

Aah, yes. Kevin put me on the right track...

The first column is the time of each sample. The second column is the voltage of channel 1 (see the X1 in the first row?) The third column is the voltage on channel 3.

The trigger is generally in the center, at Time = 0, and every time stamp to the left of that will be negative.

If you are looking for the delay from Channel 1 to Channel 3, then negative time stamps shouldn't cause any problems.

Scan through Channel 1, looking for an edge. If you find it, note the time (T1). Now scan through Channel 3 looking for an edge, and note the time (T3). The difference (T3-T1) is the delay. It doesn't matter where the edge is, the math will always work. If there are multiple edges, or T3 might sometimes be before T1, you may have to change your scanning algorithm, but the math will stay the same.

Al

Disclaimer: For more reliable response, you should consider calling your local Agilent Technical Call Center. The Agilent Forums are monitored on an "as available" basis, and aren't necessarily the fastest way to get technical questions answered.

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3 Replies

algoss Oct 18, 2013 4:58 AM
Mark Correct
Correct Answer
What are you expecting to see? What does your signal look like?

Al

Disclaimer: For more reliable response, you should consider calling your local Agilent Technical Call Center. The Agilent Forums are monitored on an "as available" basis, and aren't necessarily the fastest way to get technical questions answered.
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ksmith Oct 21, 2013 8:42 AM
Mark Correct
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Modern digital scopes can capture pre-trigegr data. The trigger time is defined as T = 0, so any timne befoire that is negative, i.e. before the trigger event.
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- algoss @ ksmith on Oct 22, 2013 5:37 AM
  Mark Correct
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  Aah, yes. Kevin put me on the right track...
  
  The first column is the time of each sample. The second column is the voltage of channel 1 (see the X1 in the first row?) The third column is the voltage on channel 3.
  
  The trigger is generally in the center, at Time = 0, and every time stamp to the left of that will be negative.
  
  If you are looking for the delay from Channel 1 to Channel 3, then negative time stamps shouldn't cause any problems.
  
  Scan through Channel 1, looking for an edge. If you find it, note the time (T1). Now scan through Channel 3 looking for an edge, and note the time (T3). The difference (T3-T1) is the delay. It doesn't matter where the edge is, the math will always work. If there are multiple edges, or T3 might sometimes be before T1, you may have to change your scanning algorithm, but the math will stay the same.
  
  Al
  
  Disclaimer: For more reliable response, you should consider calling your local Agilent Technical Call Center. The Agilent Forums are monitored on an "as available" basis, and aren't necessarily the fastest way to get technical questions answered.
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