Hi,

I'm using 4395A to measure power in dB form.

I want to convert from power (dB) to current (A) via 4395A SA mode.

Is this feasible? If not, is there other ways for the conversion?

Please advise.

I'm using 4395A to measure power in dB form.

I want to convert from power (dB) to current (A) via 4395A SA mode.

Is this feasible? If not, is there other ways for the conversion?

Please advise.

> Hi,

>

> I'm using 4395A to measure power in dB form.

>

> I want to convert from power (dB) to current (A) via 4395A SA mode.

>

> Is this feasible? If not, is there other ways for the conversion?

>

> Please advise.

Perhaps I am mis-understanding your question, but this sounds trivial.

The definition of dBm is

dBm = 10 * Log_base_10(power_in_mW)

re-arranging:

Power (mW) = 10^(dBm/10)

e.g.

-10 dBm = 0.1 mW = 100 uW

0 dBm = 1 mW

3.02 dBm = 2 mW

10 dBm = 10 mW

20 dBm = 100 mW

30 dBm = 1000 mW = 1W

Power (Watts) = I^2 R

The spectrum analyzer will have 50 Ohm inputs.

then it is a trivial bit of re-arranging a couple of equations to get the RMS current I.

Perhaps you are hoping the Agilent 4395A can do this directly for you. I don't know the instrument, but I've never met a spectrum analyzer that reads current directly.

I'm sorry if I have mis-understood you. If I have, perhaps you could clarify matters.

Dave