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AW: vrf Peaks of a measurement

Question asked by a.kieser on Nov 7, 2001
Thank you for your answer.
My problem is that the peaks are not equal high and that I want to detect
the maxima exactly, I'm not interested in the values around them.
Any Ideas?

With best regards,
Axel Kieser
___________________________
Francotyp-Postalia AG & Co. KG
TEM - Mechanical Development Department
Triftweg 21-26
16547 Birkenwerder
Germany
Tel.: +49 (0) 33 03/5 25 - 6 37
Fax: +49 (0) 33 03/5 37 07 - 6 37
mailto:a.kieser@francotyp.com
http://www.francotyp.com/



-----Ursprngliche Nachricht-----
Von: CLINE,TED (A-Loveland,ex1) [mailto:ted_cline@agilent.com]
Gesendet am: Mittwoch, 7. November 2001 20:15
An: 'a.kieser@francotyp.com'
Cc: vrf@lvld.agilent.com
Betreff: RE: vrf Peaks of a measurement


Hello Axel,

Try the attached "findpks.vee" VEE 5.01 example program?



Hope this helps!

| Ted Cline
| IO Support
| Basic, Emerging and Systems Technologies (BEST) PGU
| Agilent Technologies
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IO Libraries:
  http://www.agilent.com/find/iolib
  http://www.agilent.com/find/iolibux

VEE:
  http://www.agilent.com/find/vee

BASIC for Windows:
  http://www.agilent.com/find/basic

Instrument Drivers:
  http://www.agilent.com/find/inst_drivers
  http://www.agilent.com/find/inst_drivers_pnp



> From: a.kieser@francotyp.com [mailto:a.kieser@francotyp.com]
> Sent: Wednesday, November 07, 2001 9:26 AM
> To: vrf@lvld.agilent.com
> Subject: vrf Peaks of a measurement
>
>
> Hi,
> I have a measurement y=f(x) in a 2D-Array where are at
> several times peaks
> which are e.g. threetimes higher than the normal signal. Does
> anybody know a
> simple method to collect the x-values of the measurement in
> an array? A
> Matlab-Solution would be nice, too.
>
> Thanks in advance,
>
> Axel Kieser
> ___________________________
> Francotyp-Postalia AG & Co. KG
> TEM - Mechanical Development Department
> Triftweg 21-26
> 16547 Birkenwerder
> Germany
> Tel.: +49 (0) 33 03/5 25 - 6 37
> Fax: +49 (0) 33 03/5 37 07 - 6 37
> mailto:a.kieser@francotyp.com
> http://www.francotyp.com/





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